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Analyze the time complexity of BFS

#1
04-26-2024, 03:38 PM
BFS checks spots one level at a time starting from your chosen point. You mark each spot when it gets visited so nothing repeats. I see the queue holding the next ones in order as you move along. But every link from a spot must get looked at too. You count those checks because they pile up fast in big setups. And the whole process stays quick if connections stay few. Maybe your graph spreads wide with lots of loose ends. Perhaps the effort stays tied to all spots plus their links. Now you notice no extra work creeps in from repeats or backtracks. Then the speed holds steady across most graphs you try.

I watch how a full table of connections would force extra scans each step. You avoid that by using simple neighbor lists instead. But the time still rises when links multiply across the whole thing. And sparse areas finish early while crowded zones drag on. You tally the visits and end up with effort that matches the size exactly. Perhaps a lone starting spot reaches everything in one sweep. I know you wonder about cases with disconnected parts. But each separate chunk adds its own spots and links to the total. Now the method handles them by restarting from new points. Then the overall pace stays the same without sudden jumps.

Your choice of how to store the links changes little in the end. I find lists let you grab neighbors right away without hunting. But a full grid makes you skip empty rows often. You still cover every real link once at most. And this keeps the growth steady rather than exploding. Maybe your graph sits small and finishes in moments. Perhaps bigger ones with thousands of ties test the limits. I think you see why the method beats deeper searches in wide spaces. But the queue can swell if levels get huge all at once. Now memory use joins the time picture without changing the core count. Then you adjust by picking better storage when needed.

The best graphs let BFS run in steps that grow only with the parts shown. You avoid wasted effort on already seen areas through simple marks. And edges between distant spots get ignored until their turn arrives. I notice dense clusters force more neighbor checks per spot. But the total never exceeds the sum of everything present. Perhaps you test on random shapes and see the pattern hold. Now uneven distributions shift the work toward busier sections. Then the method proves reliable for finding shortest paths in steps. You gain insight into why it suits certain searches over others. And practice with varied sizes shows the linear pattern clear.

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bob
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Analyze the time complexity of BFS - by bob - 04-26-2024, 03:38 PM

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Analyze the time complexity of BFS

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