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Describe inorder traversal of a binary tree

#1
08-27-2019, 10:23 AM
You know how inorder works by hitting the left branch before anything else. I always tell you to think of it as going deep left until you can't. Then you process the current spot. But then you swing over to the right side after. It feels natural once you try it a few times on paper.

You weave through nodes by first chasing every left child down. I see you nodding when the root gets visited right after that left run ends. Then the right child opens up for the same pattern to repeat. Recursion keeps stacking these left first moves until leaves block further progress. You end up with nodes appearing in ascending order if the tree stays sorted like in search structures.

But empty trees just skip everything without a single visit happening. I remind you single node cases output that lone value immediately since no branches exist. The whole process runs in linear time because each node gets touched exactly once across all calls. Space grows with tree height from the call stack building up during deep left dives. You notice balanced trees keep that space reasonable while skewed ones eat more memory.

Also the pattern differs from other orders by placing the root in the middle slot of the sequence. I watch you realize why this produces sorted output in binary search setups every single time. Then right subtrees mirror the left logic after the root step finishes. Partial runs on subtrees let you build bigger results without restarting from scratch. You handle unbalanced cases by letting recursion manage the uneven depths automatically.

Perhaps stack based versions replace recursion when you want to avoid call overhead in big trees. I show you pushing left paths first then popping to visit before shifting right. But the core left root right logic stays identical in those loops. You track parents manually with the stack to mimic what recursion does behind the scenes. Edge cases like all left leaning trees force the stack to hold almost everything before visits start.

Now threaded trees let you follow links instead of stacks for constant space tricks during these traversals. I bet you see how that avoids extra memory while preserving the visit order. Then successor pointers guide you rightward after each root step. You still follow left first but without piling up frames. Grad level tweaks often involve such space optimizations for massive datasets.

Or consider how inorder fits expression trees by yielding infix notations naturally from the structure. I tell you the operators land between operands because of that middle visit timing. Then leaf values come out in the proper sequence for evaluation. You combine this with other traversals for full tree processing in compilers or parsers. Depth first nature means you finish one subtree completely before moving on.

You measure efficiency by counting visits which always totals the node count regardless of shape. I note the worst case stack height hits the full node number in chains. But average cases stay logarithmic for balanced forms common in practice. Then you apply it to database indexes where sorted output speeds up range queries. Partial trees let you stop early if only a subtree matters for your task.

Also recursion depth limits appear in languages with fixed stack sizes during huge left chains. I suggest you switch to iterative when those limits bite. Then parent pointers in nodes can replace external stacks for another variant. You debug by tracing the order on small examples to catch off by one mistakes. The method scales to any binary shape without changes to the core logic.

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bob
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Describe inorder traversal of a binary tree

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